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use linker to align fpu state save area

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This commit is contained in:
Ben Gras
2012-04-19 15:06:47 +02:00
parent 093c949274
commit a149be43fc
11 changed files with 45 additions and 81 deletions
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22
kernel/proc.c
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@@ -136,6 +136,9 @@ void proc_init(void)
rp->p_scheduler = NULL; /* no user space scheduler */
rp->p_priority = 0; /* no priority */
rp->p_quantum_size_ms = 0; /* no quantum size */
/* arch-specific initialization */
arch_proc_init(i, rp);
}
for (sp = BEG_PRIV_ADDR, i = 0; sp < END_PRIV_ADDR; ++sp, ++i) {
sp->s_proc_nr = NONE; /* initialize as free */
@@ -155,25 +158,6 @@ void proc_init(void)
ip->p_rts_flags |= RTS_PROC_STOP;
set_idle_name(ip->p_name, i);
}
#if (_MINIX_CHIP == _CHIP_INTEL)
for (rp = BEG_PROC_ADDR; rp < END_PROC_ADDR; ++rp) {
/*
* FXSR requires 16-byte alignment of memory image, but
* unfortunately a.out does not preserve the alignment while
* linking. Thus we have to do manual alignment.
*/
phys_bytes aligned_fp_area;
aligned_fp_area =
(phys_bytes) &rp->p_fpu_state.fpu_image;
if(aligned_fp_area % FPUALIGN) {
aligned_fp_area += FPUALIGN -
(aligned_fp_area % FPUALIGN);
}
rp->p_fpu_state.fpu_save_area_p =
(void *) aligned_fp_area;
}
#endif
}
static void switch_address_space_idle(void)